What is the Gibbs free energy change for an
electrochemical cell where the cell potential is
0.16 volts and the overall process transfers 3
electrons?
Answer in units of kJ/mol.
Funny, just solved this one
The equation is delta G = -nFE
so its delta G = (-3)(96485)(.16)
which would give u -46312.8
since its asking for kJ, u divide my 1000
giving you -46.3128