Free Energy – Power Generator

First independant FREE energy Generator with NO moving parts!
Charls Flynn has a US Patent from 1997 on the Generator Core!
Read more about it and many other great inventions on free energy devices in the PJKBOOK PDF on: “www.free-energy-info.co.uk”

Duration : 0:10:34


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This post was written by admin who has written 408 posts on Your Own Energy!.

25 Responses to “Free Energy – Power Generator”

  1. hijackednation 13. Oct, 2009 at 4:04 pm #

    how many watts …
    how many watts input and how many watts output?

  2. exposed777 13. Oct, 2009 at 4:04 pm #

    Ok, I am no expert …
    Ok, I am no expert or anything but doesn’t an AC current need a “push” not just a flip flop if you get what I mean.
    As in this system it flips but it doesn’t give a drag like if you go with a magnet over a coil, you have to go past it not just still, so to get a flow of electrons (very small flow, the electrons move back and forth non the less).
    +schematic looks simple enough but why haven’t you build it for yourself and shown us here? As that confuses me and makes me disbelieve it.
    Thanks :)

  3. brandoncheatem 13. Oct, 2009 at 4:04 pm #

    Could you possibly …
    Could you possibly send me a copy of more detailed plans. I would like to build a working system myself.

  4. keebordcowboy 13. Oct, 2009 at 4:04 pm #

    live2laugh111, get …
    live2laugh111, get UPDATE, get some education. kids in 1 grade know that changing polarity is generating electricity. take a peak for “Kapanadze” This man,is form Georgia, this is country in the middle east, if you don’t know. His MEG is not working too.. and it is 5KW, also in Turkey they made 100KW generator, by his idea..if you don’t know how to do it, don’t hesitate the others. this principle is dully simple.

  5. live2laugh111 13. Oct, 2009 at 4:04 pm #

    Don’t waste your …
    Don’t waste your time on this, it won’t work!! I’ve built plenty of these types of magnetic flux switching circuits (including the one shown) and they WILL NOT PRODUCE ANY ELECTRICITY.
    You have to have some sort of motion associated between magnet and core in order to produce electricity. A mere change in flux won’t do it, despite what Faraday claims (try it if you don’t believe me).

    Ted

  6. joelaroint1 13. Oct, 2009 at 4:04 pm #

    how do you get a …
    how do you get a patent without a working unit ?

  7. kosmopolita1 13. Oct, 2009 at 4:04 pm #

    the first …
    the first succesfull unit needs to be build
    to prove the concept….

  8. growtallerkey 13. Oct, 2009 at 4:04 pm #

    very low volume …
    very low volume sound…..i have to close my ear on my speakers

  9. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    The capacitor (50µF …
    The capacitor (50µF) used to switch the transistor can be a normal polarized one but I think the polarity has to be wired the wrong way. The other one has to be bipolar (non-polarized).

  10. 31elvin 13. Oct, 2009 at 4:04 pm #

    Are both capatitors …
    Are both capatitors non-polorized ?

  11. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    Since it seems to …
    Since it seems to be difficult to get core material that can handle higher frequencies it seems best to tune the powering circuit directly to the desired output frequency and give L3 so many windings that you reach the desired output voltage directly (without power converter).

    And now, YES we will need another separate L3 coil with way less windings to reach the 12 Volt to power the input.

  12. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    ¡Hola, yo no he …
    ¡Hola, yo no he construido el generador! Usted le debe desarrollar su ser (diámetro de Alambre/vueltas/tamaño de centro de hierro…. Los más fuertes sus imanes el mejor (Neodym N52). Usted puede enrollar L2 como un aircore o combinar con un rollo L1 (bifiliar). ¡!!! ¡L3 tiene que tener para duplicar por lo menos la masa de cobre que L1!!! Ejemplo: L3 = 1 Kg/L1 = 0,5Kg & L3 = 1 Mm/L1 = 0,2mm Lea (lo traduce) todos los comentarios al video.
    Tome Cuidado

  13. jlmocj 13. Oct, 2009 at 4:04 pm #

    quisiera armarlo …
    quisiera armarlo pero le faltan datos como seria:
    de que tamaño es el laminado, el diámetro de las bobinas, cuantas vueltas llevan las bobinas, los imanes son de neodimio o ferrita, la bobina l2 se monta encima de l1 o se coloca a un lado lleva núcleo de aire o de fierro, deberías de dar mas datos.

    ?usted ya la armo, y le funciono

    Perdoné por escribir en español.

  14. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    I know this is a …
    I know this is a little bit of topic but take a look at the “RODIN COIL” on youtube.

  15. sjh7132 13. Oct, 2009 at 4:04 pm #

    No, sorry it won’t …
    No, sorry it won’t work. If you really believe it will, build one and demonstrate it.

  16. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    In short: “yes”
    In short: “yes”

  17. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    When somebody …
    When somebody builds it ;-)

  18. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    !Keep in mind the …
    !Keep in mind the difference in distance! (permanent North to permanent South & permanent North to coil South)

  19. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    !!! L3 has to have …
    !!! L3 has to have at least double the mass of copper than L1 !!!

    Example: L3 = 1Kg / L1 = 0,5Kg & L3 = 1mm / L1 = 0,2mm

    Read all the comments to the video and read the PDF file befor asking questions please.

    Take Care

  20. ExoSanty 13. Oct, 2009 at 4:04 pm #

    this is what tom …
    this is what tom baerden did with his meg, right?

  21. freedomfidaj 13. Oct, 2009 at 4:04 pm #

    It’s all good … …
    It’s all good … And when you can look at the device working on this scheme?

  22. sjh7132 13. Oct, 2009 at 4:04 pm #

    The flaw in the …
    The flaw in the theory is that a small megnetic field can reroute a larger one. A piece of metal isn’t a magnetic transistor. The fields simply add like vectors.

  23. winsonali 13. Oct, 2009 at 4:04 pm #

    search for video …
    search for video with winsonali and you will find a working model of the same system with a little difference

  24. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    … I am using …
    … I am using cylindrical magnet Ø10mm and length 30mm. The magnet is magnetized along the axis, it means one side of that rod is N, another is S. To achieve desired B, I insert more such magnets in parallel.
    When I inserted all, then I measured B again (without L1activated). The result was 0,386T, and 0,391T (left and right).

    After that I activated the coil L1 and got:

    !!!! 0,761T (left side) and 0,002T (rigt side) or when I changed the polarity by L1, then 0,003 and 0,781. !!!!

  25. TheGuru2You 13. Oct, 2009 at 4:04 pm #

    Physical mesurments …
    Physical mesurments taken by another youtuber I have private contact with show different:

    … I am using gaussmeter with 1 mm-sensor.
    My first test was to check if the magnetic flux is
    redirected or not. I used for it DC signal.
    If in the core were no magnets, then I measured B in the gap in both sides appr. the same … 0,341T and 0,386T. Then I changed the current-direction in the coil L1 and the B
    changed to ….. -0,351T and -0,386T.

    After that I inserted two groups of magnets …

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